把BBD公式中的笑脸做成选股

编写要求：

股票网解答：

网友求助：

源码为：

{BBD}

ZZ:=(HHV(H,3)+LLV(L,3))/2;A:=IF(C>ZZ,VOL,0);B:=IF(C<ZZ,VOL,0);总0:=(A-B);
BBD:EMA(总0,3)/SUM(VOL,5)*100,LINETHICK0;

STICKLINE(BBD>=0 AND BBD>REF(BBD,1),0,BBD,8,0),COLOR000088;
STICKLINE(BBD>=0 AND BBD>REF(BBD,1),0,BBD,5,0),COLOR0000AA;
STICKLINE(BBD>=0 AND BBD>REF(BBD,1),0,BBD,3,0),COLOR0000CC;
STICKLINE(BBD>=0 AND BBD>REF(BBD,1),0,BBD,0.5,0),COLOR0000FF;
STICKLINE(BBD>=0 AND BBD<REF(BBD,1),0,BBD,8,0),COLOR880088;
STICKLINE(BBD>=0 AND BBD<REF(BBD,1),0,BBD,5,0),COLORAA00AA;
STICKLINE(BBD>=0 AND BBD<REF(BBD,1),0,BBD,3,0),COLORDD00DD;
STICKLINE(BBD>=0 AND BBD<REF(BBD,1),0,BBD,0.5,0),COLORFF00FF;

STICKLINE(BBD<0,0,BBD,8,0),COLOR008800;
STICKLINE(BBD<0,0,BBD,5,0),COLOR00AA00;
STICKLINE(BBD<0,0,BBD,3,0),COLOR00DD00;
STICKLINE(BBD<0,0,BBD,0.5,0),COLOR00FF00;
XH1:=REF(BBD,1)<REF(BBD,2) AND REF(BBD,1)<-10 AND BBD>REF(BBD,1) AND BBD>0;
XH2:=REF(BBD,1)>=REF(BBD,2) AND REF(BBD,1)>8 AND BBD<REF(BBD,1) AND BBD<0;
DRAWICON(XH1,0-2,1);DRAWICON(XH2,0+2,2);

①周:=REF(EMA(C,5),1);
②周:=REF(EMA(C,10),1);
③周:=REF(EMA(C,15),1);
④周:=REF(EMA(C,20),1);
⑤周:=REF(EMA(C,25),1);
⑥周:=REF(EMA(C,30),1);
①X:=EMA(C,5)-①周;
②X:=EMA(C,10)-②周;
③X:=EMA(C,15)-③周;
④X:=EMA(C,20)-④周;
⑤X:=EMA(C,25)-⑤周;
⑥X:=EMA(C,30)-⑥周;
DT2:=①X>=0 AND ②X>=0 AND ③X>=0 AND ④X>=0 AND ⑤X>=0 AND ⑥X>=0;
KT2:=①X<0 AND ②X<0 AND ③X<0 AND ④X<0 AND ⑤X<0 AND ⑥X<0;
GT2:=NOT(DT2) AND NOT(KT2);
AA:=DT2 AND( REF(①X,1)<0 OR REF(②X,1)<0 OR REF(③X,1)<0 OR REF(④X,1)<0 OR REF(⑤X,1)<0 OR REF(⑥X,1)<0);
BB:=GT2 AND (REF(①X,1)<0 AND REF(②X,1)<0 AND REF(③X,1)<0 AND REF(④X,1)<0 AND REF(⑤X,1)<0 AND REF(⑥X,1)<0);
XG1:=AA OR BB;
XG2:=BBD>0 AND BBD>REF(BBD,1) AND REF(BBD,1)<0;
STICKLINE(XG1 AND XG2,0,BBD/2,8,0),COLOR008888;
STICKLINE(XG1 AND XG2,0,BBD/2,5,0),COLOR00AAAA;
STICKLINE(XG1 AND XG2,0,BBD/2,3,0),COLOR00CCCC;
STICKLINE(XG1 AND XG2,0,BBD/2,0.5,0),COLOR00FFFF;

不胜感激！！！

解答如下：

zz:=(hhv(h,3)+llv(l,3))/2;
a:=if(c>zz,vol,0);b:=if(c<zz,vol,0);总0:=(a-b);
BBD:=EMA(总0,3)/SUM(VOL,5)*100;
XH1:REF(BBD,1)<REF(BBD,2) AND REF(BBD,1)<-10 AND BBD>REF(BBD,1) AND BBD>0;

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